How many carbon monoxide molecules are in 0.75 moles of carbon monoxide

Hello!

Firstly, we need to determine the atomic formula of carbon monoxide.

When breaking down the name, we know that there is only one carbon atom since we normally do not add the prefix mono- (one), in the front of the first element. Secondly, there is one oxygen atom since mono = one, and oxide is oxygen. Carbon monoxide is written as: CO.

Now, to find the number of molecules, we will need to use a conversion factor, and also we must know Avogadro's number: 6.02 x 10^23 molecules.

To set up the conversion factor, we must change the units from "moles CO" to "molecules CO". To do that, we will begin with the given number, "0.75 moles CO", and multiply that by "6.02 x 10^23 molecules CO over 1 mol CO".

0.75 moles CO x (6.02 x 10^23 molecules CO / 1 mol CO) = 4.52 x 10^23 molecules CO

Therefore, there are about 4.52 x 10^23 molecules CO.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g