The molarity (m) of an aqueous solution containing 29.8 g of sucrose, c12h22o11, in 120 ml of solution is: 2.58 x 10–2 m. 7.26 x 10–4 m. 1.38 m. 0.726 m.

0.726 mol·L⁻¹

Step-by-step explanation:

c = moles/litres

Moles = 29.8 × 1/342.30

Moles = 0.087 06 mol

Litres = 120 × 1/1000

Litres = 0.120 L

c = 0.087 06/0.120

c = 0.725 mol·L⁻¹

b i think it’s a water wheel turning in a stream

chemistry sucks a**

explanation: