The following solutions are prepared by dissolving the requisite amount of solute in water to obtain the desired concentrations. rank the solutions according to their respective osmotic pressures in decreasing order assuming the complete dissociation of ionic compounds. rank from highest to lowest osmotic pressure. to rank items as equivalent, overlap them. 1m c6h12o6, 1m mgcl2, 2m ch3oh, 1m nacl

C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂

Step-by-step explanation:

The formula for osmotic pressure (Π) is

Π = icRT

If T is constant,

Π = kic

C₆H₁₂O₆:

Π = k × 1 × 1 = k

MgCl₂:

Π = k × 3 × 1 = 3k

CH₃OH:

Π = k × 1 × 2 = 2k

NaCl:

Π = k  × 2 × 1 = 2k

The order of osmotic pressures is  

C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied