Use the equation below to determine how many liters of nh3 are needed to react completely with 10.0 l of n0 at stp

Answer is: 6.66 L of NH3 are needed to react completely.

Balanced chemical equation: 4NH₃ + 6NO  → 5N₂ + 6H₂O.

V(NO) = 10.0 L; volume of nitrogen(II) oxide.

V(NH₃) = ?

Vm = 22.4 L/mol; molar volume at STP.

n(NO) = V(NO) ÷ Vm.

n(NO) = 10 L  ÷ 22.4 L/mol.

n(NO) = 0.446 mol; amount of nitrogen(II) oxide.

From balanced chemical equation: n(NO) : n(NH₃) = 6 : 4

0.446 mol : n(NH₃) = 6 : 4.

n(NH₃) = 0.3 mol; amount of ammonia.

V(NH₃) = 0.3 mol · 22.4 L/mol.

V(NH₃) = 6.66 L.

here are some of the ways in which chemical and nuclear reactions differ.

explanation: