Nan experiment, chemists heated a solid, red substance in a test tube. vapors from the heated red substance condensed as a metallic liquid on the side of the tube. the red substance eventually disappeared, leaving only the metallic liquid and producing a gas that escaped from the tube. which statement best describes what happened to the red substance in this experiment? a. the experiment demonstrates the formation of plasma from the red substance. b. the experiment demonstrates a physical property of the red substance. c. the experiment shows that the red substance experienced a chemical change. d. the experiment shows that the red substance can be a solid, liquid, or gas. e. the experiment shows that the red substance is an element.

Answer is: C. The experiment shows that the red substance experienced a chemical change.

This is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

This is example of chemical decomposition.

Chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

Chemical decomposition is opposite of chemical synthesis.

c

Explanation:

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%