The following equation is one way to prepare oxygen in a lab. 2kclo3 → 2kcl + 3o2 molar mass info: mm o2 = 32 g/mol mm kcl = 74.55 g/mol mm kclo3 = 122.55 g/mol if 25.6 g of kcl are produced, then how many moles of kclo3 were consumed? 0.209 mol 0.687 mol 0.343 mol 0.172 mol

The moles of KClO₃  that were consumed  is  0.343  moles

    calculation

2KClO₃ →  2KCl +3O₂

 step  1: find the  moles    KCl

moles   = mass÷ molar mass

 25.6 g÷74.55 g/mol =0.343  moles

Step 2 : use the  mole  ratio to determine    the  moles  KClO₃

  from  equation above KClO₃ : KCl  is 2:2  =1:1

     therefore   the  moles  KClO₃  = 0.343  moles

it is the most commonly accepted one