Use the periodic table to determine the electron configuration for iodine (i). express your answer in noble gas condensed form.

The atomic number for iodine (I) = 53

The electron for I is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵

Now, among the noble gases, Krypton (Kr) has an atomic number 36. Thus we can write:

I = [1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ ] 5s² 4d¹⁰ 5p⁵

I = [Kr] 5s² 4d¹⁰ 5p⁵

(or)

I = [Kr]  4d¹⁰ 5s² 5p⁵

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"