A72.84 g sample of ba(oh)_2ba(oh) 2 is dissolved in enough water to make 1.700 liters of solution. how many ml of this solution must be diluted with water in order to make 1.000 l of 0.100 m ba(oh)_2ba(oh) 2

Answer : 399.8 ml of solution must be diluted with water.

Solution : Given,

Mass of = 72.84 g

Volume of solution = 1.7 L

Molarity of water = 0.1 mole/L

Volume of water = 1 L

First we have to calculate the molarity of solution.

Formula used :

where,

M = molarity of solution

= mass of

= molar mass of

= volume of solution

Now put all the given values in this formula, we get

Now we have to calculate the volume of solution.

Formula used :

where,

= molarity of solution

= molarity of water

= volume of solution

= volume of water

Now put all the given values in this formula, we get

By rearranging the term, we get

      (1 L = 1000 ml)

Therefore, 399.8 ml of solution must be diluted with water.

i'm not sure

explanation:

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