Determine the theoretical yield of hcl if 60.0 g of bcl3 and 37.5 g of h2o are reacted according to the following balanced reaction. a possibly useful molar mass is bcl3 = 117.16 g/mol. bcl3(g) + 3 h2o(l) → h3bo3(s) + 3 hcl(g)

   The   theoretical yield  of  HCl  produced  is  56.06  grams  of HCl

    calculation

BCl₃(g) +3 H₂O(l) →   H₃BO₃(s)  + 3 HCl(g)

Step 1: find the  moles of   each reactant

 moles  = mass÷molar mass

moles  of BCl₃  =  60.0 g÷117.16 g/mol =0.512  moles

moles  of H2O  = 37.5 g ÷18 g/ mol = 2.083  moles

Step 2: use the  moles  ratio  to determine  the limiting reagent

from  the  equation above BCl₃ :HCl  is 1:3 therefore the moles of HCl =  0.512 moles x 3/1 =1.536  moles

H2O :HCl  is 3:3 = 1:1 therefore  the moles of  HCl is also 2.083  moles

Bcl₃  is  the limiting   reagent since it produces  less  amount  of HCl   therefore the   moles   HCl is 1.536  moles

Step 3 ; find the  theoretical  yield

The theoretical yield =  moles x molar mass

from periodic table the molar mass  of HCl = 1+ 35.5=  36.5 g/mol

Theoretical yield= 1.536 moles  x  36.5 g/mol =56.06 g  of Hcl

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.