How many grams of sodium hydroxide are present in 247.0 ml of a 0.300 m naoh solution?

 The grams  of NaOH  that are  present  in 247.0  ml  of  a 0.300M NaOH solution   is  2.964 grams

calculation

Step  1: find moles of NaOH

moles  = molarity  x  volume in liters

volume in liters  = 247.0 /1000 =  0.247  liters

molarity =   0.300 M = 0.300  mol/l

moles = 0.300 mol/l   x 0.247 =0.0741  moles

step 2: find mass  of NaOH

mass=  moles x molar mass

The  molar mass of NaOH = 23 +1 +16= 40 g/mol

mass=0.0741  moles x40 g/mol =2.964 grams

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.