Asample of gas has an intial volume of 22.8 l at a pressure of 1.65 atm. if the sample is compressed to a volume of 10.7 l, what is its pressure? (assume constant temperature.)

 The  pressure  of the  gas  is 3.52 atm

calculation

This is calculated using the Boyle's  law  formula

that is  P1V1= P2V2  where;

P1 = 1.65   atm

V1 =22.8 L

P2 =? atm

V2  = 10.7 L

make P2 the subject of the formula by  dividing    both side by V2

P2 = P1V1 / V2

P2 = (1.65 atm x 22.8 l) / 10.7 L  =  3.52   atm