Al2(so4)3(s) + h2o(l) al2o3(s) + h2so4 (aq) calculate enthalpy formation for this reaction. balance the reaction. calculate the total enthalpy change that would occur from 15 moles of al2(so4)3

The given chemical equation is:

On balancing the equation we get,

Calculating enthalpy of formation of this reaction from the standard heats of formation of the products and reactants:

Δ

=[(-1669.8kJ/mol)+ {3* (-909.27 kJ/mol)}]-[(-3442kJ/mol)+{3*(-285.8 kJ/mol)}]

=[(-4397.61kJ/mol)]-[(-4299.4kJ/mol)]

=-98.21kJ/mol

Total enthalpy change when 15 mol of reacts will be=

since electrons are negative the answer is neagtaive