Consider the reaction: hcl(aq) + naoh(aq) → naoh(aq) + h2o(l) how much 0.113 m naoh solution will completely neutralize 1.25 l of 0.228 m hcl solution? express your answer in liters to three significant figures.

 The amount of NaOH   formed  is   2.522 L

calculation

HCl  +NaOH → NaCl  +H2O

Step 1:find the  moles of HCl  =  molarity x  volume in liters

    =  1.25 l  x  0.228 M   = 0.285 moles

step 2:  use the   mole ratio to  calculate the moles of NaOH

the  mole ratio of NaOH:HCl  = 1:1 therefore the  moles  of NaOH  is also

= 0.285  moles

Step 3:  find the  volume  of  NaOH

volume =  moles /molarity

=  0.285   /0.113  = 2.522 L

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."