Write a generic lewis structure for the elements in the oxygen family (group 6a).

If we talk about elements of group 6a , they have 6 electrons in the outermost shell as the group number indicates. There are 6 elements in group 6a including  oxygen (O), sulfur (S), and selenium (Se), the metalloid tellurium (Te), and the metal polonium (Po).

The general electronic configuration of its all elements is ns^2, np^4 . They need only two electrons to complete their octet therefore, many exist as anions. Their generic Lewis dot is mentioned in the figure and here X indicates group 6a elements.

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"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

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