The half-life of carbon-14 is 5,730 years. dating organic material by looking for c-14 can’t be accurately done after 50,000 years. suppose a fossilized tree branch originally contained 4.30 grams of c-14. how much c-14 would be left after 50,000 years? use the formula n = n0 . a tree branch that originally had 4.3 grams of carbon-14 will have grams after 50,000 years.

0.0102 g

Explanation:

A common formula for determining the amount of sample remaining in terms of its half-life is

where

t = 50 000 yr

      Calculate n

n = 50 000/5730

n = 8.726

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N₀ = 4.30 g                       Calculate N

N = 4.30 × 2.36 × 10⁻³

N₀ = 0.0102 g

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

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