An evaluation of r was performed, following the procedure described in this module. the barometric pressure was 736 torr, the temperature was 295k and volume of hydrogen gas collected was 35.6 ml. the calculated value of r was 82.1 ml atm k-1 mol-1. 1) how many grams of magnesium metal were used? 2) if the vapor pressure of water had not been taken into account, what would have been the calculated value of r? 3) if the springe volume had been incorrectly read, giving a calculated system volume of 25.6 ml, what would have been the percent error in the calculated value of r?

**40** points asapessay questions (10 points possible) clear image of next, create your own scenario. it can be one of your own real experiences or one you make up. use imagery in your writing to give your instructor a the setting and an action taking pace in your writing explain the structure and functions of the skin at work in your scenario. !

What happens when light is scattered?

Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent. true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight. a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol