How many grams of nacl are required to make 150.0 ml of a 5.000 m solution

Answer : The mass of NaCl required is 43.83 g.

Solution : Given,

Volume of solution = 150 ml

Molarity of solution = 5 mole/L

Molar mass of NaCl = 58.44 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of a solution.

Formula used :

where,

= mass of solute

= molar mass of solute

= volume of solution in liter

In this question, the solute is NaCl.

Now put all the given values in this formula, we get

By rearranging the term, we get the mass of NaCl.

Therefore, the mass of solute (NaCl) required is 43.83 g.