How many grams of hydrogen peroxide (h2o2) must be added to 1,500 ml of water to produce a concentration of 1.33 m (molal solution)? (recall that the density of water is 1.0 gram/ml.)

Given:

1,500 mL of water

1.33 m (molal solution

Required:

grams of hydrogen peroxide (H2O2

solution:

1.33 molal = 1.33 m = 1.33 moles H2O2/kg water

1 gram/liter of water (1 liter/1000 mL) (1500mL)(1 kg/1000g) = 0.0015 kg water

1.33 moles H2O2/kg water (0.0015 kg water) = 0.001995 moles H2O2

Molar mass of H2O2 = 34 g/mol

0.001995 moles H2O2 (34 g/mol) = 0.068 grams H2O2

d. temperate deciduous forest

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.