1.compare and contrast the rate of solution formation between the three physical forms of salt that were placed in the vial and not agitated with the three forms of salt that were placed in the vial and were agitated.
2. on the basis of your results, what is the relationship between the temperature of the solvent and the rate of solution formation?
3. use your knowledge of collision theory to explain the results of your experiments in this laboratory.

The stable form of salt at standard temperature and pressure is solid. If you add water to salt, it will dissolve. However, there are certain factors that affect the rate of solution formation of salt. The rate of formation of salt solution is faster when the vial is agitated than when it is not agitated. By agitating the solution, you are increasing the surface area of the salt particles in contact with water.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.