22.4 l of a gas at a temperature of 0*c are at a pressure of 2.0 atm. how many moles of gas are contained in the sample?

The moles of gas are contained in the sample is 2 (two) moles

Explanation:

We will use the formula PV=nRT

R= Regnault constant

n=number of moles

We convert the temperature into Kelvin according to: 0°C= 273K. In this case, the temperature is 273L.

PV=nRT   2 atm x 22,4l = n 0,082 l atm/K mol  x 273K

n = 2 atm x 22,4l/0,082 l atm/K mol  x 273K= 2 moles

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explanation:

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