How many different e2 products can form from the dehydrohalogenation of 2-bromobutane?

We have to get the number of eliminated products formed from dehydrohalogenation of 2-bromobutane.

The number of eliminated products formed from dehydrohalogenation of 2-bromobutane is two. The products are (i) 1-butene and (ii) 2-butene.

In 2-bromobutane, bromine is attached at C-2 position of butane. From 2-bromobutane, proton from β-position gets eliminated and bromide gets released.

There are two β-H atoms with respect to leaving group Br⁻: one H-atom is at C-3 position and other one is at C-1 position.

Hence, two different products are formed on elimination reaction of 2-bromobutane.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.