Butane burns is shown in the balance chemical equation 2c4h10+1302-> 10h2o+8co2. if 6 mol of butane of carbon dioxide are produced.

Given:

Number of moles of butane = 6

To determine:

Moles of carbon dioxide produced

Explanation:

The chemical reaction involving combustion of butane is:

2C4H10 + 13O2 → 10H2O + 8CO2

Based on the reaction stoichiometry:

2 moles of butane produces 8 moles of CO2

Therefore, 6 moles of butane would yield:

6 moles C4H10 * 8 moles CO2/2 moles butane = 24 moles of CO2

Ans: If 6 mole of butane burns 24 moles of CO2 will be produced.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2