The volume (in l) that would be occupied by 5.00 mols of 02 at stp is

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K   (Given)

By rearranging the above ideal gas law equation, we get

Now put all the given values in this expression, we get the value of volume.

Therefore, the volume of oxygen at STP is 112.0665 L

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