Areaction of 55.1 g of na and 31.1 g of br2 yields 35.4 g of nabr. what is the percent yield?

So,

% yield equals actual mass of product divided by theoretical mass of product times 100%.

1. First, write the balanced reaction.

2. Since we are given the masses of both reactants, we need to do a Limiting Reactant calculation.  Calculate the theoretical masses of product produced by each reactant, assuming excess of the other reactant.

a.

b.

c. Bromine is the limiting reactant, and the theoretical mass of NaBr is:

3. Now, we can calculate % yield.

So, the percent yield is 88.5%.

Hope this helps!

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.