A/1 * b/c =d you discover a chemical reaction that produces 3 moles of valuable propane for every 7 moles of carbon supplied. essentially, this is an exchange rate of 3 moles of propane for every 7 moles of carbon. if you have 1.5 moles of carbon, how many moles of propane can you produce using this reaction? round your answer to the nearest tenth of a mole (one decimal place). input the number with no units

                  0.64 Moles of Propane

Data:

         Moles of Carbon  =  1.5 mol

         Conversion factor  =  7 mol C produces = 3 mol of Propane

Solution:

             As we know,

                7 moles of Carbon produces =  3 moles of Propane

Then,

            1.5 moles of Carbon will produce  =  X moles of Propane

Solving for X,

                     X =  (1.5 moles × 3 moles) ÷ 7 moles

                     X  =  0.6428571 moles of Propane

Or rounded to two significant figures,

                     X =  0.64 Moles of Propane

i believe it is c.) 1575 j.