Chemistry, 04.07.2019 04:00 autumnhuls5720

Why does a liquid’s rate of evaporation increase when the liquid is heated?

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Answer from: sarahbug56

the conversion of liquid to vapours is a change in state of a system from one state to other

there are basic two differences between three states of matter

1. thermal energy: gas has highest thermal energy tthen liquid and least us of solids

2. intermolecular forces of attractions

solids have highest intermolecular forces of attraction , then liquid and least in gas

sovas we increase the temperature the forces if attraction decrease s and thermal energy increases.

So when we heat liquid more moleculws gets energised attaining thermal motion in the range of gas thus the rate if evaporation increases.

Answer from: leshayellis1591

liquid’s rate of evaporation increase when the liquid is heated, due to the increase in the kinetic energy of liquid molecules.

Explanation:In liquids mostly molecules are attracted to other molecules by the process of Van der Waals attraction or dipole dipole forces like hydrogen bonds in water.These forces are weaker than covelent bonds.As the temperature of a liquid is increased, the kinetic energy of molecules also increases.Which causes the faster movement of molecules, due to this faster movement the weak dipole interactions between molecules breaks.As the interactions breaks, molecules will leave the surface of liquid turning into vapor.Hence by increasing the temperature of liquid the rate of evaporation can also be increased.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

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