The half life of carbon is 5,730 years. what fraction of the original 14/6 c would be in a wooden axe handle that was 17,190 years old? (plz explain how u got it step by step if u can t^t)

The study of chemicals and bonds is called chemistry.

The correct answer to the question is 1/8years.

According to the question, the solution is as follows:-

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.  After one half-life, half (50 %) of the original amount will remain.  After a second half-life, half of that amount (25 %) will remain, and so on.

The formula used to solve the question is as follows:-

The formula used to check the half-life:-

Thus the half-life 17190 is .

Hence, the correct answer is 1/8.

For more information about the half-life, refer to the link:-

link

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

We can construct a table.

No of half-lives  Fraction remaining

            1                        

            2                        

            3                        

The general formula is

where n = the number of half-lives.

Thus, of the original carbon remains after 17 190 y.

u i forgot the answer?