Hi is there anyone who could me with this problems plz

The relationship between K and C is K = C + 273;

or C = K - 273

Using the second equation, the equivalent temperature in C can be calculated as follows:

1a. 273K = 273-273 = 0C

b. 373K = 373-273 = 100C

c. 0K = 0-273 = -273C

d 80K = 80-273 = -193C

Using the first equation, the equivalent temperature in K:

2a. 273C = 273+273 = 546K

b. 373C = 373+273 = 646K

c. 0C = 0+273 = 273K

d. 80C = 80+273 = 353K

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.