What volume of nitrogen gas is produced when 103 liters of nitrogen monoxide react? ( all gassed are at stp)

51.5 L

Explanation:

1. Write the chemical equation.

You don’t give the reaction. However, if all the N₂ comes from NO, we can write a partial equation. The important point is that we must balance the N atoms.

      2NO + … ⟶ N₂ + …

V/L:  2 L              1 L

2. Calculate the volume of N₂.

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

According to the law, 2 L of NO produce 1 L of N₂.

Then, the conversion factor is

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol