If 14.9 kg of al reacts with an excess of fe2o3, how many kg of al2o3 will be produced?

28.144 g of , then the balanced chemical reaction is:

It is given that is present in excess, so it is an excess reagent and Al is the limiting reagent.

Now, 2 moles of Al produces 1 mole of , which means that (2×27g) = 54g of Al produces 102g of .

Therefore, 14.9g of Al will produce =

                                                          = 28.144g of

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