Chemistry, 06.07.2019 13:00 daniel6760

Asample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. which compounds could the sample be?

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Answer from: qorderiusnewton

The two possible compounds are;

1) Dimethyl Ether H₃C--O--CH₃

2) Ethanol H₃C--CH₂--OH

Solution:

Step 1: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 52.14 ÷ 12.01

Moles of C = 4.341 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 13.13 ÷ 1.01

Moles of H = 13.00 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 34.73 ÷ 16.0

Moles of O = 2.170 mol

Step 2: Find out mole ratio and simplify it;

C H O

4.341 13.00 2.170

4.341/2.170 13.00/2.170 2.170/2.170

2 5.99 1

2 6 1

Hence, Empirical Formula = C₂H₆O

Result:

As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,

1) Dimethyl Ether H₃C--O--CH₃

2) Ethanol H₃C--CH₂--OH

Answer from: Quest

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

Answer from: Quest

explanation:

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Asample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.7...