You have 47.0 ml of a 0.400 m stock solution that must be diluted to 0.100 m. assuming the volumes are additive, how much water should you add?

Hey there!

Moles of stock solution:

47.0 mL in liters : 47.0 / 1000 => 0.047 L

n = M * V

n = 0.400 * 0.047

n = 0.0188 moles

Volume final :

M = n / V

0.100 = 0.0188 / V

V = 0.0188 / 0.100

V = 0.188 L =>  188 mL

Therefore Watter added :

volume final - volume initial

188 mL - 47.0 mL =>  141 mL

Hope That helps!

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

hi my dude or dudette