What is the mass of a sample of aluminum that absorbs 596 j of heat when the temperature is raised from 30.0°c to 100.1°c? specific heat of aluminum = 0.900 j/g oc

Answer is: the mass of a sample of aluminum is  9.45 grams.

ΔT = 100.1°C - 30.0°C.

ΔT = 70.1°C.; change in temperature of a sample of aluminium.

Cp(Al) = 0.900 J/g·°C; specific heat capacity for aluminium.

Q = 596 J; heat absorbed.

Q = m(Al) · ΔT · Cp(Al).

m(Al) = Q ÷ (ΔT · Cp(Al)).

m(Al) = 596 J ÷ (70.1°C · 0.900 J/g·°C).

m(Al) = 9.45 g; mass of aluminium sample.

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

lol idk man i guess u gotta ask bill nye the science guy