How many jolie’s are required for melting 12.8 g of ice at 0 degree celsius

It takes 4,270 Joules of energy to melt 12.8 grams of ice at 0 °C.

The enthalpy change for melting ice is called the enthalpy of fusion. Its value is 6.02 kJ/mol. This means for every mole of melting ice, we must apply 6.02 kJ of heat. We can calculate the heat needed with the following equation:

= Δ

where:

q = heat

n = moles (0.71 mole = 12.8 g water)

ΔH = enthalpy (for water at 0 temperature is 6.02)

This problem can be broken into three steps:

1. Calculate moles of water

2. Multiply by the enthalpy of fusion

3. Convert kJ to J

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