Banced equation for albr3+cl2=alcl3+br2

The balanced equation is 2AlBr₃ + 3Cl₂ ⟶ 2AlCl₃ + 3Br₂

Step 1. Start with the most complicated-looking formula (AlBr₃?) and balance its atoms.

Al: Already balanced — 1 atom each side.

Br: We have 3 Br on the left-hand side and 2 Br on the right. the lowest common multiple of 3 and 2 is 6. Put a 2 in front of AlBr₃ and a 3 in front of Br₂.

2AlBr₃ + Cl₂ ⟶ AlCl₃ + 3Br₂

Step 3: Balance Al

We now need 2Al on the right to balance the 2 Al on the left. Put a 2 in front of AlCl₃.

2AlBr₃ + Cl₂ ⟶ 2AlCl₃ + 3Br₂

Step 4. Balance Cl.

We have 6 Cl on the right, so we need 6 Cl on the left. Put a 3 in front of Cl₂.

2AlBr₃ + 3Cl₂ ⟶ 2AlCl₃ + 3Br₂

The balanced equation is

2AlBr₃ + 3Cl₂ ⟶ 2AlCl₃ + 3Br₂