Ahunk of up gold weighs 800 gram to heat the gold up to a temperature of 200 kelvin if the gold absorbs 12 kilojoules of energy what was the initial temperature of the gold? the specific heat capacity of gold is 0.129 grams times c

The initial temperature of the gold was 84 K.

Step 1. Calculate the temperature change.

The formula for the heat (q) absorbed is

q = mCΔT

We can solve this equation to get

ΔT = q/(mC)

q = 12 000 J; m = 800 g; C = 0.129 J·K⁻¹g⁻¹

∴ ΔT = 12 000 J/(800 g × 0.129 J·K⁻¹g⁻¹) = 116 K

Step 2. Calculate the initial temperature

ΔT = T_f – T_i = 200 K – T_i = 116 K

T_i = 200 K – 116 K = 84 K

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3