What is the radiation particle used in the bombardment of boron-10? boron-10 plus a radioactive particle yields nitrogen-13 plus a neutron?

In the given nuclear reaction, one of the reactant is Boron-10, and the products are Nitrogen-13 and neutron. So, the sum of mass numbers of Nitrogen - 13 and neutron is 13 + 1 =14 and the sum of atomic numbers is 7 + 0 = 7 on the product side. On the reactant side the other reactant will have a mass number of 14 - 10 = 4 and an atomic number of 7-5 = 2. So, the other reactant will be alpha particle.

This nuclear reaction representing the bombarding of Boron-10 with the radioactive alpha particle to yield Nitrogen-13 and a neutron is:

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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