Chemistry, 09.07.2019 08:00 rlumanlan549

Asample of a smokestack emission was collected into a 1.25-l tank at 752 mm hg and analyzed. the analysis showed 92% co2, 3.6% no, 1.2% so2, and 4.1% h2o by mass. what is the partial pressure exerted by each gas?

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Answer from: TabbyKun00

Answer :

Partial pressure of $P_{CO_{2}}$ = 639.952 mmHg

Partial pressure of $P_{NO}$ = 36.757 mmHg

Partial pressure of $P_{SO_{2}}$ = 5.757 mmHg

Partial pressure of $P_{H_{2}O}$ = 69.533 mmHg

Solution : Given,

Total pressure, $P_{T}$ = 752 mmHg

From the periodic table, the molar masses of $CO_{2}$ , NO, $SO_{2}$ and $H_{2}O$ are 44, 30, 64, 18 respectively.

92% $CO_{2}$ by mass means 92g $CO_{2}$ is present in 100g of smoke.

3.6% NO by mass means 3.6g NO is present in 100g of smoke.

1.2% $SO_{2}$ by mass means 1.2g $SO_{2}$ is present in 100g of smoke.

4.1% $H_{2}O$ by mass means 4.1g $H_{2}O$ is present in 100g of smoke.

step 1 : First calculate the number of moles of each gas.

Formula used :

Number of moles = $\frac{\text{ Given mass}}{\text{ Molar mass}}$ ........(1)

Moles of $CO_{2}$ , $n_{CO_{2}}$ = $\frac{92g}{44g/mole}$ = 2.09 moles

Moles of NO, $n_{NO}$ = $\frac{3.6g}{30g/mole}$ = 0.12 moles

Moles of $SO_{2}$ , $n_{SO_{2} }$ = $\frac{1.2g}{64g/mole}$ = 0.018 moles

Moles of $H_{2}O$ , $n_{H_{2}O}$ = $\frac{4.1g}{18g/mole}$ = 0.227 moles

Total number of moles, $n_{T}$ is calculated as

$n_{T}$ = $n_{CO_{2}}$ + $n_{NO}$ + $n_{SO_{2} }$ + $n_{H_{2}O}$ = 2.09 + 0.12 + 0.018 + 0.227 = 2.455 moles

step 2 : Now calculate the partial pressure of each gas.

Formula used :

$P_{x}=\frac{n_{x} }{n_{T}}\times P_{T}$ .........(2)

where,

$P_{x}$ = partial pressure of x

$n_{x}$ = moles of x

$n_{T}$ = total moles

$P_{T}$ = total pressure

Now put all the values in above formula (2), we get

$P_{CO_{2}}=\frac{n_{CO_{2}} }{n_{T}}\times P_{T}$ = $\frac{2.05}{2.455}\times 752mmHg$ = 639.952 mmHg

$P_{NO}=\frac{n_{NO} }{n_{T}}\times P_{T}$ = $\frac{0.12}{2.455}\times 752mmHg$ = 36.757 mmHg

$P_{SO_{2}}=\frac{n_{SO_{2}} }{n_{T}}\times P_{T}$ = $\frac{0.018}{2.455}\times 752mmHg$ = 5.5136 mmHg

$P_{H_{2}O}=\frac{n_{H_{2}O} }{n_{T}}\times P_{T}$ = $\frac{0.227}{2.455}\times 752mmHg$ = 69.533 mmHg

Answer from: Quest

mechanics (greek is that area of science concerned with the behaviour of physical bodies when subjected to forces or displacements, and the subsequent effects of the bodies on their environment. the scientific discipline has its origins in ancient greece with the writings of aristotle and archimedes[1][2][3] (see history of classical mechanics and timeline of classical mechanics). during the early modern period, scientists such as galileo, kepler, and newton laid the foundation for what is now known as classical mechanics. it is a branch of classical physics that deals with particles that are either at rest or are moving with velocities significantly less than the speed of light. it can also be defined as a branch of science which deals with the motion of and forces on objects. the field is yet less widely understood in terms of quantum theory.

explanation:

Answer from: Quest

i'm assuming that the correct answer is indeed the first one/ "a"..

An object is transported from the earth to the moon which statement is true about the object

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Asample of a smokestack emission was collected into a 1.25-l tank at 752 mm hg and analyzed. the ana...