Which of the following is a valid mole ratio from the balanced equation 2c3h6 + 9o2 → 6co2 + 6h2o? 1 mole of c3 h6/ 2 moles of c o2 6 moles of h2 o/ 9 moles of o2 2moles of c3 h6/ 6 moles of o2 3 moles of h2 o/ 2 moles of c o2

                  6 moles of H₂O / 9 moles of O₂

The Balance Chemical Equation is as follow,

                                    2 C₃H₆ +  9 O₂     →   6 CO₂  + 6 H₂O

According to this balance equation 2 moles of C₃H₆ (Propene) when combusted with 9 moles of O₂ (Oxygen) produces 6 moles of CO₂ (Carbon Dioxide) and 6 moles of H₂O (Water Vapors).

Hence, Given options are;

1 mole of C₃H₆ / 2 moles of CO₂: This is incorrect because 1 mole of C₃H₆ will produce 2 moles of CO₂.

6 moles of H₂O / 9 moles of O₂: This is correct as 6 moles of H₂O is produced by reacting 9 moles of O₂.

2 moles of C₃H₆ / 6 moles of O₂: This ratio is incorrect because for complete oxidation 2 moles of C₃H₆ requires 9 moles of O₂.

3 moles of H₂O / 2 moles of CO₂: This is also incorrect because the production of 3 moles of H₂O will be accompanied by the production of 3 moles of CO₂.