Acompound with the empirical formula so has a molecular weight of 96.13 amu. the molecular formula is s_o_

Molecular mass / empirical mass = number with with the empirical formula needs to be multiplied to get molecular formula

Empirical mass = Atomic mass of S + atomic mass of O = 32.07 + 16 = 48.07

molar mass = 96.13 g

So ratio = 96.13 / 48.07 = 2

Hence the molecular formula = S2O2

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2