(a) how many milliliters of a stock solution of 6.0 m hno3 would you have to use to prepare 110 ml of 0.500 m hno3? (b) if you dilute 10.0 ml of the stock solution to a final volume of 0.250 l, what will be the concentration of the diluted solution?

a) in this we are diluting a stock solution, so we can use the dilution formula

c1v1 = c2v2

where c1 is concentration and v1 is volume of the stock solution

c2 is concentration and v2 is volume of the diluted solution to be prepared

substituting the values

6.0 M x V = 0.500 M x 110 mL

V = 9.17 mL

9.17 mL of the stock solution should be taken and diluted upto 110 mL to prepare the 0.500 M solution

b)

In this question we are given the volume taken from the stock solution , we have to find the concentration of the diluted solution

again we use the dilution formula, c1v1 = c2v2

substituting the values

6.0 M x 10.0 mL = C x 250 mL

C = 0.24 M

the concentration of diluted solution is 0.24 M

i would say b

explanation:

but i think i would need more information than that