What mass of oxygen is present in this sample of znco3, which contains 3.11×1022 o atoms?

The given compound is ZnCO3

So each mole of ZnCO3 will have three moles of Oxygen atoms

So if the number of oxygen atoms in the sample = 3.11×10^22

It means the moles of oxygen atoms = number of atoms / Na (avagadro's number)

moles of oxygen atoms = 3.11×10^22 / 6.023 X 10^23 = 0.0516 moles

Mass of oxygen atoms = moles X atomic mass = 0.0516 X 16 = 0.8256 g

hurricanes form in warm water

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.