If 1.87 g‎ of acetic acid (ch3co2h)‎ reacts with 2.31 g‎ of isopentylalcohol (c5h12o)‎ to give‎ 3.20 g of isopentylacetate (c7h14o2)‎, what is the percent yield of the reaction?

The reaction of acetic acid with isopentyl alcohol is

CH3COOH + C5H12O  ---> C7H14O2  + H2O

Thus one mole of acetic acid reacts with one mole of isopentyl alcohol to give one mole isopentyl acetate

Molar mass of acetic acid = 60.05 g / mole

Moles of acetic acid used = Mass used  / Molar mass = 1.87/ 60.05 = 0.0311

Molar mass of isopentyl alcohol = 88.15 g / mole

Moles of isopentyl alcohol = Mass / Molar mass = 2.31 / 88.15 = 0.0262

Molar mass of isopentyl acetate = 130.19 g / mole

Moles of isopentyl acetate = 3.20 / 130.19 = 0.0246

As per equation 0.0262  should of isopentyl alcohol should react with 0.0262 moles of acetic acid to give 0.0262 isopentyl acetate

Thus theoretical yield = 0.0262 moles

Actual yield = 0.0246

% yield = Actual yield X 100 / theoretical yield = 0.0246 X 100 / 0.0262 = 93.89%

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.