Phosphoric acid (h3po4) is tribasic, with pka's of 2.14, 6.86, and 12.4. the charge of the ionic form that predominates at ph 3.2 is

Correct answer is .

Phosphoric acid is a polyprotic acid having 3 acidic hyrdogen therefore it will have 3 pka values.

The equations for the release of acidic hydrogen can be written as:

From the pka values we can judge the idea of pH as using Henderson-Hasselbalch Equation, we get the relation between pH and pka.

Using the following equation, relation of pH and pka is

Using this equation, we can find that the equation having pka= 2. 14 is closest to the pH=3.2 so the ionic form in this equation will be dominant at the same pH.

Therefore at pH=3.2 the ionic form of is dominant.

Phosphoric acid (H3PO4) is tribasic, with pKa's of 2.14, 6.86, and 12.4. The charge of the ionic form that predominates at pH 3.2 is H2PO4-

Phosphoric acid (H3PO4) is tribasic, with pKa's of 2.14, 6.86, and 12.4. The charge of the ionic form that predominates at pH  3.2 is __________.

Phosphoric acid, also called orthophosphoric acid, (H3PO4), is the most important oxygen acid of phosphorus. It is used to make phosphate salts for fertilizers. Phosphoric acid also used in dental cements, albumin derivatives, the sugar and textile industries.

A tribasic or triprotic acid is contains three potential protons to donate. Phosphoric acid (H3PO4) is tribasic, with pKa's of 2.14, 6.86, and 12.4.

The pKa value is method to indicate the acid strength. It is the negative log of the acid dissociation constant or Ka value. A lower pKa value indicates a stronger acid. Hence the lower value indicates the acid more fully dissociates in water.

The relation between pH and pKa is

The charge of the ionic form that predominates at pH 3.2 is the pH that close to it which is B) H2PO4- = pH = 6.86

Grade:  9

Subject:  chemistry

Chapter:  biochemistry

Keywords: Phosphoric acid, tribasic, pka, the ionic form, The charge

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).