If two fatty acids, glycerol, and a phosphate group undergo a dehydration reaction, what molecule forms

            A Phospholipid is formed.

                   The reaction of fatty acids, glycerol and phosphoric acid is given below. In this reaction the carboxylic groups of fatty acids and the hydrogyl groups of glycerol undergo an Esterification Reaction with the elimination of two water molecules and formation of Ester functional group. Also, the third hydroxyl group of glycerol undergo dehydration reaction with phosphoric acid. The resulting molecule is known as phospholipid.

                    Biologically, Phospholipids are found in the cell membranes. The long hydrocarbon chains of fatty acids acts as hydrophobic (water fearing) tails and the phosphate group acts as hydrophilic (water loving) head. They form a barrier protecting the internal environment of cell from external surrounding.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

yes

explanation:

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