Asolution contains 5 grams of glucose per 100 milliliters. each mole of glucose weighs 180 grams. how many miles are there in 200 milliliters of the glucose solution? me will greatly appreciate it: )btw this is conversion problem

              Mole  =  0.055 mol

Step 1: Calculate Mass of Glucose in 200 mL solution:

As,

                     100 mL Solution contains  =  5 g of Glucose

So,

                  200 mL Solution will contain  =  X g of Glucose

Solving for X,

                        X  =  (200 mL × 5 g) ÷ 100 mL

                        X =  10 g of Glucose

Step 2: Calculate Moles for 10 g of Glucose:

As,

                                            Mole  =  Mass ÷ M.Mass

M.Mass of Glucose  =  180 g.mol⁻¹

So,

                                            Mole  =  10 g ÷ 180 g.mol⁻¹

                                            Mole =  0.055 mol

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :