Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mechanism for this overall reaction is shown below. no(g) + br2(g) br2(g) (fast step; keq = k1/k−1) k2 nobr(g) + no(g) → 2 nobr(g) (slow step) what is the rate law for formation of nobr in terms of reactants based on this mechanism

The overall reaction is given by:

The fast step reaction is given as:

The slow step reaction is given as:

(slow step )

Now, the expression for the rate of reaction of fast reaction is:

The expression for the rate of reaction of slow reaction is:

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as takes place in this reaction.

The expression of rate of formation is:

=    (1)

Now, consider that the fast step is always is in equilibrium. Therefore,

Substitute the value of in equation (1), we get:

=

=

Thus, rate law of formation of in terms of reactants is given by .

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.