Which of these methods could be used to separate an insoluble solid from a soluble solid? melting the mixture and then using a filter to separate out the soluble solid melting the mixture, mixing it with water, and then using a magnet to separate out the insoluble solid mixing the mixture with water and then using chromatography to separate the two dissolved solids mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid

Answer : The correct option is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.

Explanation :

"The given mixture contains a soluble solid and an insoluble solid.

When water is added to this mixture, the soluble solid will get dissolved in water whereas the insoluble solid will remain as it is.

This will give us a heterogeneous mixture where we can see 2 distinct phases , one containing the dissolved solid and the other having undissolved solid.

In order to separate these 2 phases, we can use a simple filtration method.

When the mixture is filtered, we will get solution having soluble solid and the insoluble solid will remain on the filter paper.

This will separate the 2 solids.

To regenerate the dissolved solid, we can evaporate the water by heating it. This will give us back our original soluble solid.

Therefore, the only option that is consistent with this method is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid"

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.