When ammonium nitrate (nh4no3) explodes, the products are nitrogen, oxygen and water. when 40 grams of ammonium nitrate explode, 14 grams of nitrogen and 8 grams of oxygen form. how many grams of water form?

              18 g of H₂O

Solution:

The Balance Chemical Reaction is as follow,

                              2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation ,

              160 g (2 mole) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                       40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                      X =  (40 g × 72 g) ÷ 160 g

                      X  =  18 g of H₂O

When 40 g of ammonium nitrate explode, 14 g of nitrogen, 8 g of oxygen and 18 g of water are formed.

Let's consider the balanced equation for the decomposition reaction of ammonium nitrate.

2 NH₄NO₃ → 2 N₂ + O₂ + 4 H₂O

According to Lavoisier's law of conservation of mass, the sum of the masses of the reactants must be equal to the sum of the masses of the products over a chemical reaction. The mass of water formed is:

When 40 g of ammonium nitrate explode, 14 g of nitrogen, 8 g of oxygen and 18 g of water are formed.

You can learn more about Lavoisier's law here:

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explanation:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.