When a piece of metal mass of 56.15 g is dropped into a graduated cylinder containing 22.77 ml of water, the water level rises to 28.49 ml. what is the density o?

When a metal piece is dropped into water, the volume of water level increases. The increased volume of water is equivalent to volume of the metal piece. Also, density of any substance is mass per unit volume,so, the density of the metal piece can be calculated by dropping it in a known amount of water and measuring how much amount of  water rises.The increased volume of water is equivalent to volume of the metal piece.

Before dropping metal piece into water volume of water was 22.77 ml and after dropping the metal into water the water level rises to 28.49 ml. Rise of volume of water= (28.49 - 22.77) ml= 5.72 ml

So, volume of metal piece is 5.72 ml and mass of metal piece is 56.15 g. So- density of metal piece= mass of metal/rise in volume of water= (56.15/5.72) g/ml=9.81 g/ml=9.81 g/cm³.

there are two significant figures.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.